Give your child's math skills a boost in the Class 5 level with these area and perimeter worksheets – designed specifically for grade 5 students! Download these free, printable worksheets now to help your child hone their understanding of perimeter and area.

**Understand the Basics of Perimeter and Area**.

Before completing the math worksheets, it’s important that your child understands the basics of perimeter and area. Perimeter is the total distance around a two-dimensional shape and can be thought of as walking around its border. Area on the other hand, measures how much space a two-dimensional figure covers and is typically expressed in square units.

**Calculate the Perimeter of a Geometric Figure.**

To calculate the perimeter of a geometric figure, add up all the side lengths. For example, the perimeter of a square with sides that are 4 cm long is 16 cm (4+4+4+4). Similarly, the perimeter of a rectangle with sides that measure 6 cm and 10 cm long is 32 cm (6+10+6+10).

**Find the Area of a Square or Rectangle.**

To calculate the area of a square or rectangle, use the formula: length times width. Length is the longest side and width is the shortest side. For example, if you have a square with sides that are 5 cm long, then the area is 5 × 5 = 25 cm² (5 x 5). For a rectangle with sides that measure 8 cm and 10 cm long, the area is 80 cm² (8 x 10).

**Solve for the Area of a Triangle.**

To calculate the area of a triangle, use Heron’s formula. Find the semi-perimeter of the triangle by adding together all three sides and dividing it by two. Then, plug in the lengths for each side, plus the semi-perimeter into Heron’s formula to solve for the area. For example, if a triangle has sides measuring 6 cm, 8 cm, and 10 cm, then its area would be 24 cm² (0.25 × √[(6 + 8 + 10) × (8 + 10 - 6) × (10 + 6 - 8) × (6 + 8 - 10)]).

**Learn About Irregular Shapes and Their Areas.**

To calculate the area of an irregular shape, one must break it up into familiar shapes like triangles, rectangles, and circles whose areas can be easily determined. For example, if the irregular shape is composed of two rectangles side by side and a triangle on top, break it up into those three parts and use each formula to solve for its area. In this case, you will find the area of the two rectangles and then add them together with the area of the triangle to get your final answer.

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**Area and perimeter class 5th formulas **

**Rectangle:**Perimeter of rectangle: P = 2(L + W) Area of rectangle: A = L × W Where P is the perimeter, A is the area, L is the length, and W is the width of the rectangle.**Square:**Perimeter of square: P = 4s Area of square: A = s² Where P is the perimeter, A is the area, and s is the side length of the square.**Triangle:**Perimeter of the triangle : P = a + b + c Area of a triangle: A = 0.5 × base × height Where P is the perimeter, A is the area, a, b, and c are the side lengths of the triangle, and base and height are the lengths of the base and the height of the triangle, respectively.

**perimeter and area class 5 extra questions with solution**

Here are the sums on area and perimeter for class 5 students which will help you to understand applying formulas on perimeter and area for different figures.

**Question: A rectangular playground is 25 meters long and 15 meters wide. Calculate the perimeter and area of the playground.**

Solution: Perimeter of the rectangle = 2(L + W) = 2(25 + 15) = 2(40) = 80 meters. Area of the rectangle = L × W = 25 × 15 = 375 square meters.

**Question: A square garden has a side length of 12 meters. Calculate the perimeter and area of the garden.**

Solution: Perimeter of the square = 4s = 4 × 12 = 48 meters. Area of the square = s² = 12 × 12 = 144 square meters.

**Question: A triangle has side lengths of 5 meters, 12 meters, and 13 meters. Calculate the perimeter of the triangle. If the triangle is a right-angled triangle with the 5-meter and 12-meter sides being perpendicular, calculate the area of the triangle.**

Solution: Perimeter of the triangle = a + b + c = 5 + 12 + 13 = 30 meters. Area of the triangle = 0.5 × base × height = 0.5 × 5 × 12 = 30 square meters.

**Question: The length of a rectangle is 3 times its width. If the perimeter of the rectangle is 32 meters, find the length, width, and area of the rectangle.**

Solution: Let the width of the rectangle be W meters. Then, the length will be 3W meters. Perimeter of the rectangle = 2(L + W) = 2(3W + W) = 32 meters. => 8W = 32 => W = 4 meters So, the width is 4 meters, and the length is 3 × 4 = 12 meters. Area of the rectangle = L × W = 12 × 4 = 48 square meters.

**Question: The side length of a square is 9 meters. How much more fencing will be required to enclose the square garden compared to a rectangular garden with a length of 15 meters and a width of 3 meters?**

Solution: Perimeter of the square = 4s = 4 × 9 = 36 meters. Perimeter of the rectangle = 2(L + W) = 2(15 + 3) = 2(18) = 36 meters. The amount of extra fencing required = Perimeter of square - Perimeter of rectangle = 36 - 36 = 0 meters.

**FAQs on are and perimeter class 5th**

**Question: The length of a rectangle is 10 meters, and its width is 6 meters. Find the perimeter and area of the rectangle.**

Answer: Perimeter = 2(L + W) = 2(10 + 6) = 2(16) = 32 meters. Area = L × W = 10 × 6 = 60 square meters.

**Question: A square has a side length of 7 meters. Calculate its perimeter and area.**

Answer: Perimeter = 4s = 4 × 7 = 28 meters. Area = s² = 7 × 7 = 49 square meters.

**Question: A triangle has sides of length 3 meters, 4 meters, and 5 meters. Find its perimeter and area (assuming it is a right-angled triangle with 3-meter and 4-meter sides being perpendicular).**

Answer: Perimeter = a + b + c = 3 + 4 + 5 = 12 meters. Area = 0.5 × base × height = 0.5 × 3 × 4 = 6 square meters.

**Question: A rectangle has a perimeter of 24 meters, and its length is twice its width. Find the dimensions and area of the rectangle.**

Answer: Let the width be W meters. Then, the length is 2W meters. Perimeter = 2(L + W) = 2(2W + W) = 24 meters. => 6W = 24 => W = 4 meters Length = 2W = 2 × 4 = 8 meters. Area = L × W = 8 × 4 = 32 square meters.

**Question: The side length of a square is 5 meters. How much more fencing will be required to enclose the square compared to a rectangular garden with a length of 8 meters and a width of 1 meter?**

Answer: Perimeter of the square = 4s = 4 × 5 = 20 meters. Perimeter of the rectangle = 2(L + W) = 2(8 + 1) = 2(9) = 18 meters. Extra fencing required = Perimeter of square - Perimeter of rectangle = 20 - 18 = 2 meters.

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